Axioms and construction

How many polygons a fold reaches

The heptagon is what the extra axiom buys and it is one polygon. What it actually buys is a density: to a thousand sides a compass reaches fifty-two regular polygons and a fold reaches two hundred and seventy-five, and the ratio between them is still widening. The compass has five usable primes in the whole of arithmetic and may use each once; a fold keeps acquiring new ones and may repeat the factor of three as often as it likes.

Assumes The heptagon a compass cannot reach and The eleven-sided one nobody can fold.

The heptagon a compass cannot reach states the difference between the two tools as a condition on a single number. A compass needs n’s odd part to be a product of distinct Fermat primes; a fold needs it to be a product of distinct Pierpont primes; and seven is the first place the answers differ.

That is the right statement of the rule and it is an odd way to describe a gain. Seven is one polygon. A reader who is told that folding reaches the heptagon has been told about a single case, and the natural question — how much did the extra axiom buy — has an answer that is not a case at all.

It is a counting function, and it can be computed to any bound.

How many polygons each tool reachesThe number of regular polygons with at most n sides that each tool can construct, counted to any bound by arithmetic rather than read off a list. A compass needs n's odd part to be a product of distinct Fermat primes and only five are known; a fold needs distinct Pierpont primes and those keep arriving. The heptagon is one point on the gap, and the gap widens at every bound.050100150200250300350400020406080100120140160sides, up to npolygons reachablea fold — 155a compass — 40both sets computed by division to 400 · 4 Fermat primes and 13 Pierpont primes below it
Fig. 1 The number of regular polygons with at most n sides each tool can construct, counted by arithmetic rather than read off a list. The gap is not a fixed set of extras: it widens at every bound.

Counting rather than listing

Both sets are defined by the same shape of test and the test is short enough to run on every n.

Take Euler’s totient of n — the count of numbers below n sharing no factor with it — and factorise it. The regular n-gon is compass-constructible exactly when that factorisation is all twos, and fold-constructible exactly when it has nothing above three. Both are smoothness conditions on one number, they differ in one prime, and the same predicate decides both.

The permission to carry a three is not permission to carry it once. A compass may use each Fermat prime once and no more, since a repeated odd prime would need a second quadratic step where the tool has only one; a fold has a cubic step and may take it repeatedly, so three, nine, twenty-seven and eighty-one are all reachable by it and none of the last three by a compass.

Run that from three upwards and count. To forty sides a compass reaches sixteen polygons and a fold reaches thirty-one. To a hundred, twenty-four against fifty-nine. To four hundred, forty against a hundred and fifty-five. To a thousand, fifty-two against two hundred and seventy-five.

The ratio is 1.9, then 2.5, then 3.9, then 5.3. The extra axiom does not buy a fixed set of extras; it buys a set that is pulling away.

That is the honest answer to the question the heptagon poses, and it is more interesting than the heptagon, because a widening ratio is a statement about arithmetic rather than about a particular polygon.

Why the compass’s set stops

The two counting functions behave differently and the reason is short.

The Fermat primes known are three, five, seventeen, two hundred and fifty-seven and sixty-five thousand five hundred and thirty-seven. Five of them. None has been found since, every candidate up to enormous size has been tested and factored, and the general expectation is that there are no others.

A compass-constructible n is a power of two times a product of distinct members of that list. Five primes give thirty-two subsets, so — if the list really is complete — there are exactly thirty-two odd numbers in the whole of arithmetic that a compass can reach, and the constructible n are those thirty-two each multiplied by every power of two.

Below a hundred thousand only sixteen of the thirty-two appear, because the larger products are enormous: 3·5·17·257·65537 is more than four billion. So the compass’s counting function grows like the logarithm of the bound — it gains one every time the bound doubles, from the powers of two, and picks up a rare extra when a new product comes into range.

A logarithm is what the compass’s set does. The heptagon is not the exception to a rich set; the set was never rich.

How many polygons each tool reachesThe number of regular polygons with at most n sides that each tool can construct, counted to any bound by arithmetic rather than read off a list. A compass needs n's odd part to be a product of distinct Fermat primes and only five are known; a fold needs distinct Pierpont primes and those keep arriving. The heptagon is one point on the gap, and the gap widens at every bound.02004006008001000050100150200250300sides, up to npolygons reachablea fold — 275a compass — 52both sets computed by division to 1000 · 4 Fermat primes and 17 Pierpont primes below it
Fig. 2 The same count to a thousand. The compass’s curve is very nearly a staircase of powers of two with occasional steps where a new product of Fermat primes arrives; the fold’s is a curve.

Why the fold’s does not

Pierpont primes are primes of the form 2^a·3^b + 1, and unlike the Fermat primes they keep arriving. Below a thousand there are seventeen of them — three, five, seven, thirteen, seventeen, nineteen, thirty-seven, seventy-three, ninety-seven, a hundred and nine, a hundred and sixty-three, a hundred and ninety-three, two hundred and fifty-seven, four hundred and thirty-three, four hundred and eighty-seven, five hundred and seventy-seven, seven hundred and sixty-nine — against four Fermat primes in the same range.

The reason for the difference is worth stating because it is the whole of why the extra axiom is worth having. A Fermat prime must be one more than a power of two, and the powers of two are sparse: there are about log₂N of them below N. A Pierpont prime must be one more than a number of the form 2^a·3^b, and those are much denser: their count below N grows like the square of the logarithm rather than like the logarithm.

The candidates are squared and the primes among them follow. So the fold’s supply of usable primes does not run out in the way the compass’s does, and its constructible set keeps acquiring genuinely new odd parts rather than only new powers of two.

Whether there are infinitely many Pierpont primes is not known, and this essay does not need it to be. What is computed here is the count to a stated bound, and every number in it is arithmetic on a sieve.

What the ladder’s two rungs look like from here

The rung below this one is about the hendecagon: folding does not reach it, the obstruction is a single prime factor of five in ten, and no arrangement of cubics produces a five.

Set that beside the counting functions and the two rungs say complementary things. The fold’s set is much larger than the compass’s and it is still very thin. Two hundred and seventy-five polygons below a thousand is a little over one n in four, so nearly three in four of the small regular polygons are out of reach of a fold as well.

That is worth holding on to, because “folding beats the compass” is easy to read as “folding reaches everything the compass does not”. It reaches four times as much and misses most of arithmetic, and the misses are governed by exactly the same kind of condition as the hits.

The two sets also have the same shape of description, which is what makes the comparison possible at all. Both are “the odd part is a product of distinct primes from a list”, and the lists differ in one factor of three. The whole of what the seventh axiom buys, expressed as economically as the subject allows, is permission to include a three in the exponent, and everything above is the arithmetic consequence of that.

Which primes each tool reachesFor each small prime p, the factorisation of p − 1 and whether it clears the bar each tool sets. A compass needs p − 1 to be a power of two; a fold needs it to have no prime factor above three. Eleven is the first prime a fold cannot reach, and it is the first place folding runs out.pp − 1, factoredcompassfoldingthe regular p-gon32both tools52 · 2both tools72 · 3folding only112 · 5neither132 · 2 · 3folding only172 · 2 · 2 · 2both tools192 · 3 · 3folding only232 · 11neither292 · 2 · 7neither312 · 3 · 5neither372 · 2 · 3 · 3folding only11 is the first prime out of a fold's reach — 11 − 1 = 2 · 5the factor of five is the obstruction, and no arrangement of folds produces onea compass needs a power of two; a fold needs nothing above three
Fig. 3 The condition itself, for the small primes: p − 1 factored, and whether it clears the bar each tool sets. The count above is this table run to a bound and tallied, with the same divisions and no new argument.

The polygons in the gap, named

A widening ratio is a summary and the summary is more convincing with the contents of the gap in front of it, so it is worth listing what the seventh axiom actually adds below a hundred.

The odd numbers a compass can reach below a hundred are one, three, five, fifteen, seventeen, fifty-one and eighty-five — seven of them, being the products of distinct Fermat primes that fit. Everything else in the compass’s set is one of those times a power of two.

A fold adds every product of a power of three with distinct Pierpont primes above three, and below a hundred the new primes it brings are seven, thirteen, nineteen, thirty-seven, seventy-three and ninety-seven. Each brings itself, its doublings, and its products with the primes already there — so seven brings the heptagon, the fourteen-gon, the twenty-one-gon, the twenty-eight-gon, the thirty-five-gon and so on.

Which is the mechanism behind the widening, stated concretely. A new prime does not add one polygon; it adds a whole multiplicative family. The compass has run out of new primes and can therefore only add powers of two to families it already has; the fold keeps acquiring primes, and each one multiplies into everything already present.

That also explains the shape of the two curves. A curve gaining families grows faster than one gaining members of existing families, and the difference compounds — which is why the ratio is 1.7 at forty and 4.0 at a thousand rather than settling.

What a repeated factor costs

The distinctness condition is easy to pass over and it is doing real work, so it deserves a paragraph of its own.

Nine is three squared. Three is both a Fermat prime and a Pierpont prime, so a triangle is constructible by either tool — and a nonagon is constructible by neither, because the odd part nine has a repeated factor.

That is worth pausing on. The nine-gon is not out of reach because nine is large or awkward; it is out of reach because it is a square. And the reason is the same one that governs everything else here: the degree of cos(2π⁄9) is φ(9)⁄2 = 3, which is fine for a fold — so the nonagon is foldable, and the compass cannot have it.

So the distinctness condition is the compass’s condition, and a fold’s version of it is weaker in exactly the place that matters: a repeated three is what a cube root supplies. Nine, twenty-seven and eighty-one are all foldable and none is compass-constructible, and they are among the first entries in the gap. The nonagon is asserted in the figure rather than left to the count, and the assertion earned itself immediately.

Which sharpens the summary one more turn. The seventh axiom’s permission to include a three in the exponent is not only permission to use the prime seven; it is permission to use threes repeatedly, and the powers of three are the part of the gap that is easiest to see and hardest to notice.

Which regular polygons each tool reachesFor every n up to twenty-six, whether the regular n-gon can be constructed with straightedge and compass and whether it can be folded. The test is the same in both cases and it is about the totient of n: a power of two for the compass, and nothing above a factor of three for a fold. The heptagon is the first place the two answers differ.compassfolding3242546276the first gap8496104111012413121461581681716186191820821122210232224825202612n across the top, φ(n) underneathcompass: φ(n) a power of two — Gauss, and Wantzel's proof that nothing else worksfolding: φ(n) with no factor above three, because one fold solves a cubic
Fig. 4 The polygons themselves rather than the primes behind them, at the small sizes where the difference first bites. The heptagon is the famous entry and the nonagon is the quieter one, unreachable by a compass because nine is a square and reachable by a fold because a cube root can be taken twice.
What each toolset can reachThe numbers each construction method can produce. A compass generates square roots and so reaches degrees that are powers of two; a fold solves cubics and reaches products of powers of two and three. The gap between the two rows contains the three classical impossible problems.straightedge alonerationalno new numbers at allstraightedge and compassdegree 2^k√2, the regular 17-gonone fold at a timedegree 2^a 3^b∛2, the trisected angle, the regular 7-goneverything past here is out of reach of Euclid's toolsdoubling the cube, trisecting the angle and the regular heptagon all live in the gap
Fig. 5 What each tool’s condition amounts to, side by side. The two differ in one factor, and every count in this essay is that difference run to a bound.

What the gap does not mean

Three readings of the widening ratio are available and only one of them is supported, so it is worth separating them.

Supported: the fold’s constructible set is asymptotically much larger. The counting functions are computed and they diverge, at every bound tried, by a factor that grows.

Not supported: the fold reaches a positive fraction of all polygons. Two hundred and seventy-five of a thousand is a little over a quarter, and the fraction is falling as the bound rises — it was thirty-one of thirty-eight at forty. Both sets have density zero; one of them approaches zero much more slowly.

Not supported: a folder can actually build these. Reachability is a statement about a field and says nothing about the length of a construction, which is a separate column entirely — and nothing about accuracy, which is the rung after this one. The 769-gon is constructible by folding and nobody has folded one.

The third reading is the one worth guarding against, because a counting function is exactly the sort of result that invites it. A count of what a tool reaches is a count of what a tool’s algebra permits, and every physical question is somewhere else.

How many polygons each tool reachesThe number of regular polygons with at most n sides that each tool can construct, counted to any bound by arithmetic rather than read off a list. A compass needs n's odd part to be a product of distinct Fermat primes and only five are known; a fold needs distinct Pierpont primes and those keep arriving. The heptagon is one point on the gap, and the gap widens at every bound.0204060801001200204060sides, up to npolygons reachablea fold — 70a compass — 26both sets computed by division to 120 · 3 Fermat primes and 10 Pierpont primes below it
Fig. 6 The first hundred and twenty sides, where the two curves separate and the separation is still readable. The heptagon is the first divergence and after it they part steadily rather than in jumps.

Which theorem was checked and how

The count uses this site’s own constructibility predicate rather than a second one. The totient is computed by trial division and factorised, and the two verdicts are smoothness over two primes and over three — the same function the polygon census in the neighbouring ladder is built on, so two figures here cannot disagree about which polygons a fold reaches.

The Fermat list is checked against what is known. A sieve over p − 1 runs beside the count, and the primes it produces below the bound must be exactly three, five, seventeen and two hundred and fifty-seven — which catches an exponent slip and supplies the prime counts the figure reports.

The nonagon is asserted rather than left to the count. It is the case that separates the two conditions, and the figure refuses to draw if the two tools agree about it — a check that earned its place at once, by catching a predicate which had applied the compass’s distinctness rule to the fold and refused the best-known polygon a fold constructs.

And the widening is asserted rather than observed. The gap must be strictly larger at every mark than at the one before it, and a figure whose gap settled to a constant would refuse — which is the difference between a density and a fixed set of extras, stated as a condition on the picture existing.

Where the model stops

The Fermat list is taken as complete below the bound and no further. Nothing here proves there are only five Fermat primes; what is computed is a count to a stated bound using the primes that exist below it, which needs no conjecture.

The Pierpont primes are counted, not characterised. Whether there are infinitely many is open. The essay’s claim is about counting functions to finite bounds and does not require the answer.

Constructibility here is the classical algebraic condition and nothing else. It assumes exact folds, an unbounded plane, and unlimited construction length — three idealisations this ladder’s neighbours each spend a rung dismantling.

And a regular polygon is a regular polygon. The condition says nothing about polygons that are not regular, about approximate constructions, or about the many-fold operations that change the reachable degree entirely.

What the picture cannot show

A counting function is a summary and it hides which polygons are in the gap. The curve rising says the fold has gained; it does not say whether the gain at n is a new prime, a new product, or another power of two — and those are quite different events.

Nor can it show the size of the constructions. Every point on the fold’s curve is a polygon that some finite sequence of folds produces, and the sequences for the large ones are not short; the curve treats a heptagon and a 769-gon as one unit each.

The deepest thing it cannot show is whether the compass’s curve really has stopped. If a sixth Fermat prime exists it is astronomically large, so the curve below any bound anybody will ever draw is unaffected — and the statement “the compass’s set has thirty-two odd numbers in it” is a conjecture wearing the clothes of a count.

The idealisation, named

The whole essay lives inside the algebraic criterion, and that criterion has three assumptions in it that this ladder’s other rungs are about.

A construction may be any finite length. The 769-gon’s is not short and the criterion does not care.

A fold is exact. Every reachable n is reachable to infinite precision, and no polygon on either curve is easier or harder to draw accurately than any other.

The plane is unbounded. Every intermediate the construction needs is available, which a real sheet does not offer.

What survives all three is the comparison, because both tools are idealised identically. The ratio between the counting functions is a fact about two prime lists and would be the same fact if both tools were degraded in the same way.

Where the ladder goes next

The counting function answers “how much” and leaves “how well” untouched, and the next rung is about that.

A construction is exact in the field and a fold has an error. Propagating a landmark error through a real closure shows that the conditioning of a reference is set by the angle at which the creases fixing it cross — and that the axioms that produce shallow crossings are the conic ones, which are exactly the axioms that reach the heptagon. What buys the reach costs the accuracy makes that measurement on the same closure this ladder’s neighbours use, and the tail it finds is not in the algebra anywhere.

Sideways, the counting functions belong beside the largest polygon a square sheet holds, which crosses constructibility with an optimisation and finds the two agreeing. That agreement is about the same arithmetic seen twice, and the counting function here is what makes the coincidence look less like one.

The habit worth carrying is a question to ask whenever a capability is illustrated by an example. How many, to a bound? An example is a point and a capability is a set, and counting the set is usually cheap once the criterion is written down — as it was here, where the count needed nothing that the rung below had not already established.

What this makes readable

Essays that name this one as a prerequisite.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

What links here

Every essay whose body links to this one.

The objects this essay names

Each one links to every other essay that touches it.

Constructible numberConstructible polygonFermat primesPierpont primesReachable setTotient