What a flat sheet can become — the developable generator
developable is one function. Everything below was drawn by it when the site was
last published, at settings taken from the essays rather than invented for this page — so a figure
here is the same figure a reader meets in an essay, and when the generator changes, this
page changes with it.
With nothing specified
sub: "wet-folding"
sub: "curved-crease", radii: [0.34, 0.52, 0.7]
which: [cylinder, cone]
What it checked while it drew
Collected while it drew, not written by hand. The count is how many separate times that claim was put to the test.
- the classification covers 4 surfaces ×4
- a material that stretches 5.0% absorbs the whole excess out to 0.55 radians — 35.1% of the way to the rim — and nothing beyond it ×3
- the broken line's slope rises at every one of its 3 starts, so each start adds tucks rather than taking any away ×3
- a material giving 5.0% needs 7 rings of divisions on a 90° cap, at 0.35, 0.50, 0.62, 0.72, 0.81, 0.90, 0.98 of the way out ×2
- and it does so by 1.4 per cent, which is what the accuracy costs: the pile a start sits in is mostly the start's own three sheets and hardly at all the gathering under it ×2
- and it falls in proportion, so the 20.0% material needs 10 times fewer divisions than the 2.0% one ×2
- and the rings crowd toward the rim — the gaps between them are 0.35, 0.15, 0.12, 0.10, 0.09, 0.09, 0.08, each no wider than the last ×2
- both placements put 4 and 4 starts on a 90° cap, so the two can be compared where they sit ×2
- for every accuracy asked of a 90° cap the best placement needs no more starting radii than even spacing, and fewer once the accuracy is fine — 4 against 3 for 5.0%, 6 against 5 for 2.0%, 8 against 6 for 1.0%, 11 against 9 for 0.5%, 24 against 18 for 0.1% ×2
- placed for strain, the 4 starting radii of a 90° cap spread outward past the first piece — stretches of 0.21, 0.25, 0.26, 0.28 of the radius — and the worst strain is the excess where the first piece stops ×2
- the number of divisions falls as the material gives more — 2.0% needs 19, 5.0% needs 8, 10.0% needs 4, 20.0% needs 2 — and the count is the same whether the divisions are gores or tucks ×2
- the placement that follows the sphere best does put its deepest start in more paper — 3.37 sheets against the even placement's 3.32 — because it crowds its starts outward, where the gathering is already thicker ×2
- with 4 starts on a 90° cap and the paper taking 1.00 as much in compression as in stretch, the lowered line leaves 0.90% of stretch and 0.90% of compression — the two add to the touching line's 1.81% at every ratio ×2
- a gathered hemisphere hides 1 − 2⁄π of its rim, 36.3%, and its rim is π⁄2 sheets thick on average — both exactly ×1
- a gathered hemisphere's rim carries an excess of 1 − 2⁄π = 36.3 per cent of its own circumference, which is the quantity every answer has to dispose of ×1
- a material giving 2.0% needs 18 rings of divisions on a 90° cap, at 0.22, 0.31, 0.39, 0.45, 0.50, 0.55, 0.60, 0.64, 0.68, 0.72, 0.76, 0.79, 0.83, 0.86, 0.90, 0.93, 0.96, 0.99 of the way out ×1
- a paper that stretches 1.00% and compresses a multiple c of that needs exactly the starts a stretch-only paper giving (1 + c) times 1.00% needs — c = 0: 6, c = 0.25: 5, c = 0.5: 5, c = 1: 4, c = 2: 4, c = 4: 3 ×1
- and the rings crowd toward the rim — the gaps between them are 0.22, 0.09, 0.07, 0.06, 0.05, 0.05, 0.05, 0.04, 0.04, 0.04, 0.04, 0.04, 0.04, 0.03, 0.03, 0.03, 0.03, 0.03, each no wider than the last ×1
- at 16 starts the best spacing's advantage is within three hundredths of its limit on every cap, and on a shallow cap the limit is close to four ninths — 20° 0.468 against 0.450, 45° 0.489 against 0.472, 90° 0.588 against 0.582, 120° 0.675 against 0.666, 150° 0.679 against 0.672 ×1
- at 24 starts on a 90° cap, each stretch past the first times the predicted strain density √(sin s ⁄ s) varies by only 0.8%, so the law describes the placement ×1
- at a cap of 90° the start-count solver reproduces the strain placement's worst strain at two, four and eight starts to a part in a million ×1
- at every count of starting radii on a 90° cap the strain placement leaves less strain than even spacing and even spacing less than the length placement — 2: 13.77%, 9.97%, 7.80%; 3: 7.89%, 4.51%, 3.29%; 4: 5.34%, 2.55%, 1.81%; 6: 3.08%, 1.14%, 0.78%; 8: 2.09%, 0.64%, 0.43% ×1
- built its own way — through the curve lowered by half the touching strain, with stretch and compression checked on every piece — the crossing line for 2, 4, 8, 16 starts needs no more starts than the touching one, at exactly half the worst strain ×1
- each additional gore strictly reduces the residual strain, so the figure's trade is a real one ×1
- every doubling of the starting radii divides the largest shortfall by close to four — 2.14, 1.75, 2.22, 1.77, 2.24 — so the error falls as the square of their number ×1
- every doubling of the starting radii divides the largest shortfall by close to four — 2.99, 3.73, 3.93, 3.98 — so the error falls as the square of their number ×1
- every surface in the classification is one this figure has a verdict for ×1
- for a material giving 2.00%, 4.00%, 6.00%, 8.00%, 10.00% either way, the touching line's first start is the ring rule's first ring and the crossing line's is exactly its second — 0.31 against 0.31, 0.45 against 0.45, 0.55 against 0.55, 0.64 against 0.64, 0.72 against 0.72 of the radius ×1
- for every count of starting radii the best spacing leaves a smaller worst shortfall than even spacing, and at 16 starts the ratio is 0.588, closing on the limit 0.582 that the curvature of a 90° cap sets ×1
- I grows from 0.261 at 15° to 2.277 at 179°, toward 2.278 for a whole sphere, and a paper giving 2% needs 1, 2, 3, 3, 4, 4, 5, 5, 6, 6, 6, 6 starts touching and 1, 2, 2, 2, 3, 3, 4, 4, 4, 4, 5, 5 crossing ×1
- lowered by a cone of 1.65%, the line of hiding with 3 starts crosses the sphere's curve 5 times — hiding too little at every start and too much in the middle of every stretch ×1
- more stretch reaches a deeper cap — 2.0% to 20°, 5.0% to 32°, 10.0% to 45°, 20.0% to 65° — and none of these reaches a hemisphere ×1
- near the centre the hidden length is πs³ ⁄ 3R² to 0.01%, so a tuck that follows the sphere widens as the cube of the distance ×1
- on a 90° cap in a material giving 5.00% the first start the strain allows is the ring rule's first ring — 0.35 against 0.35 of the radius — and the strain rule needs 2 starts past the centre where the ring rule needs 7 rings ×1
- on a 90° cap the starts a paper giving ε needs never fall below I ⁄ √(8ε) and never exceed it by more than a start and a half, from 0.1 to 10 per cent of give; at two per cent it needs 4 starts touching the curve and 3 crossing it ×1
- on a cap of 90° the worst strain from m starts placed for strain is I² ⁄ 8m² times 1.164, 1.078, 1.038, 1.019, 1.009 at 2, 4, 8, 16, 32 starts — the inverse square, with a correction that dies away as one over m ×1
- on caps of 30, 60, 90, 120, 150° the worst strain over I² ⁄ 8m² falls toward one at the same rate, 1.0188, 1.0188, 1.0188, 1.0190, 1.0194 at sixteen starts — the correction is the centre's, and every cap has the same centre ×1
- so stretch alone makes no hemisphere at any of these limits, and the cap it does make grows only as the square root of the strain ×1
- the 16 pieces between starts on a 90° cap follow √(8εs ⁄ sin s) to within 0.2% past the first two, widening 25% from centre to rim, and the first, a cone from the centre, is √(6ε) wide to 0.0% ×1
- the 3 crease radii increase and all lie inside the sheet, so the alternation between them is drawn on paper that exists ×1
- the best 4 starting radii for a 90° cap are closer together the further out they are — stretches of 0.363, 0.235, 0.206, 0.196 of the radius — and leave a worst shortfall of 2.0% against 3.3% evenly spaced ×1
- the cap angle rises monotonically with the strain allowed, which is what the bisection between them depends on ×1
- tucks from the centre of a 90° cap leave their largest strain at the centre, and it equals the excess where they stop — 0.25 of the way out: 2.55%, 0.45 of the way out: 8.12%, 0.65 of the way out: 16.49% ×1
- with 4 starting radii on a 90° cap the worst strain is 5.34% placed for length, 2.55% evenly spaced and 1.81% placed for strain — the placement that was best for length is the worst of the three for the paper ×1
Where it is called
Every figure listed here is drawn by the same rule, so a mistake in the rule would be in all of them at once, and so would a correction.
A crease carries no curvature
A fold looks like the sharpest curvature a sheet could have, and intrinsically it has none at all. Developability — the first of the four conditions this site's checker runs — is exactly the statement that folding an uncut sheet creates no curvature anywhere, including at the creases.
A crease that curves
Bend a crease and the paper either side is forced into a shape nobody creased. The flat-folding theorems say nothing about it, because they are statements about straight creases meeting at a point.
A curve has no panels
A rigid folding is a finite list of flat pieces joined along lines. A curved crease has no such list, and refining one does not help: the kink at each joint falls as one over the segment count, and the total of the kinks does not fall at all, because it is a constant of the curve.
A sheet that grows cannot lie flat
A leaf does not decide to buckle. Growth changes the distances between a sheet's own material points, a set of distances determines a curvature, and a curvature that is not zero cannot be laid in a plane by anything — whatever the sheet is made of and however slowly it grew.
A start is worth an inverse square
Straight tucks gathering a flat disc into a cap leave a worst strain that falls as the starts multiply, and every essay on them counted starts without saying what one buys. It buys an inverse square. A chord of the hiding curve misses it by its width squared times the curve's bend over eight, so starts placed for strain leave a worst strain of I² ⁄ 8m², with I one integral of the cap's shape — 1.464 for a hemisphere. A paper that gives ε therefore needs about I ⁄ √(8ε) starts, a tenth of the give costs three times the starts, and letting the hiding cross the curve saves exactly a factor of √2. The same argument says why the starts spread outward, and by how much.
A straight tuck is a cone point
A tuck with straight edges hides length in proportion to how far past its start it has gone, which is a cone's law and not a sphere's. Started at the centre, straight tucks make a cone. Started at several radii, they hide length in a broken line that follows a sphere's cubic, and the worst shortfall falls as the square of the number of starting radii: 36.9 per cent of the rim's hiding from one start, 12.3 from two, 3.3 from four, 0.8 from eight. Every start is three creases at a point, which is a vertex that cannot fold flat — and it is exactly where the gathered sheet's curvature goes.
A tuck keeps what a gore cuts
A flat disc gathered into a spherical cap has more circumference than the cap, and a gore removes the excess while wet-folding stretches it away. A tuck folds it under, which keeps the sheet whole and turns the excess into thickness. At the rim of a gathered cap the paper is α ⁄ sin α sheets thick on average — π⁄2 for a hemisphere — and a simple tuck is three, so single tucks reach a cap of 130.6° before they run into one another. And because a sphere's circles fall short of a plane's as the cube of the radius, a tuck that follows the sphere widens as the cube too: its edges are curves.
Crossing the curve moves no start
The broken line of hiding that straight tucks make on a gathered cap has always been drawn touching the sphere's curve at every start, so the paper between starts can only stretch. Let it cross, and the best line turns out to be the old one lowered by a cone: the starts stay exactly where they were at every count, the worst strain halves exactly — 1.81 per cent to 0.90 on a hemisphere at four starts — and a paper that stretches one amount and compresses another places its tucks exactly as a stretch-only paper giving their sum would.
Crowd the tucks toward the rim
Straight tucks started at several radii follow a sphere's hidden length in a broken line, and evenly spaced starts leave a worst shortfall that falls as the square of their number. Evenly spaced is not the best spacing. A sphere's hiding bends hardest near the rim, so the best starts crowd outward — on a hemisphere, four of them at 0.36, 0.60 and 0.80 of the radius — and leave 38 per cent less error than four evenly spaced. As the count grows the saving closes on 42 per cent, a limit set by the square root of how the sphere's hiding bends; on a shallow dish it approaches five ninths. To follow a hemisphere within one per cent takes six rings of tucks instead of eight, and within a tenth of a per cent eighteen instead of twenty-four.
Crowding outward costs almost nothing
Placing the tuck starts for equal error crowds them toward the rim, where the gathered paper is already at its thickest, and the obvious worry is that the accuracy is bought with depth. Measured, it is not: on a hemisphere the crowded placement's deepest start sits in 3.37 sheets against the even placement's 3.32, because a start is three sheets of its own and the gathering beneath it is only one and a half.
Paper that stretches on purpose
Wet-folding breaks the assumption every theorem of flat folding rests on, deliberately. It does not repeal the geometry — it buys a few percent of strain, and a few percent of strain is worth about twenty degrees of sphere.
The gap between two curves
The rulings leaving a curved crease are not parallel, so they cross, and the surface exists only as far as the first crossing. That bound is usually read as a limit on how far a design extends outward. It is not: the paper between two curved creases has to be reachable from both, so the bound bites hardest where the circles are smallest, and a concentric pleat has a hole in the middle that no sheet size removes.
The paper reads strain
Two placements of a gathered cap's tuck starts agreed on their first radius and nobody knew why. Both were proxies. What the paper takes is the shortfall at a circle divided by the circle's length, and judged by that the first start must sit exactly where the excess reaches the material's give — and past it the starts spread outward, not in. Four radii placed for length leave a hemisphere 5.34 per cent strain; the same four placed for strain leave 1.81.
The sculptors got there first
Curved-crease folding produced its best objects decades before anybody could compute one. The surfaces were made by hand, the ruling lines that determine them were not calculated until much later, and the mathematics has been catching up ever since.
Three answers, one count
Seams, curved creases and a few per cent of stretch are the three ways round the sphere, and a tuck is a fourth. All four dispose of one quantity — the excess circumference a flat disc has over the sphere's circle — and all four dispose of it by dividing the circle. So the number of divisions needed is the same whichever answer is chosen: nineteen for a hemisphere in a material that gives two per cent, eight at five, four at ten. What differs is what a division costs, and one of the four runs out.
What a flat sheet can become
A sheet that cannot stretch cannot become a sphere. That much belongs to differential geometry; what belongs to folding is the three ways round it — seams, curved creases, and a few percent of stretch — and what each one costs.
What one cut buys
A fold moves paper about and cannot change how much of it surrounds a point. A cut can, and that one difference is the whole of what this site's founding rule is worth. Take a wedge out and the sheet closes into a cone; let one in and it has more paper than the plane will accept.
Where a ring of divisions belongs
A pattern that divides the circle everywhere as finely as its rim requires is over-divided for most of its radius, because the excess grows from nothing. Putting a ring of new divisions in wherever the residual would otherwise pass what the material takes gives seven rings on a hemisphere at five per cent of stretch, at 0.35, 0.50, 0.62, 0.72, 0.81, 0.90 and 0.98 of the way out — and the first of those sits where a completely different criterion put its first tuck start.
Where the rulings run out
A curved fold's surface is made of straight lines leaving the crease, and the lines are not parallel, so they cross. Past the first crossing there is no surface: two points of the paper have been sent to one point of space. The boundary is a curve nobody drew, no crease pattern shows it, and it sits at the sine of the ruling angle times the crease's own tightest radius — on every curve tried.
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