Axioms and construction

The axiom that names two folds

Bring one line onto another and the operation is satisfied by either of two folds, always exactly perpendicular to one another, creasing the paper in completely different places. Over four thousand random line pairs on a square, both folds land on the sheet two thousand nine hundred and sixty-five times, and the statement of the axiom does not say which one is meant. The fifth axiom is worse: its two answers are at any angle at all, from half a degree apart to square.

Assumes One fold at a time, and there are exactly seven of them and An axiom may name no fold.

There are exactly seven ways a single fold can be specified by alignments of points and lines already on the paper, and the list is complete: a fold line in the plane has two degrees of freedom, and enumerating the ways to spend two constraints is where the number seven comes from.

An axiom may name no fold is one thing that can go wrong with that picture. An alignment can have no solution — twenty-three point eight per cent of the fifth axiom’s inputs, in a square — or a solution whose crease misses the paper entirely, which happens to thirteen point three per cent of the third’s.

The other end of the same under-determination is less often mentioned and is much commoner.

Two folds, and the axiom does not choose

The third axiom brings one line onto another. Two lines that meet have two bisectors of the angle between them, and folding along either one carries the first line onto the second. Both satisfy the axiom’s statement exactly, and the statement says nothing about which.

One line onto another, by either of two foldsTwo lines drawn on a square sheet and both of the folds the third axiom names for them. Each one brings the first line onto the second; they are perpendicular to one another and they crease the paper in completely different places.the axiom is satisfied by both, and says nothing about whichthe two are square to one another, alwaysthe thin lines are the two the axiom is given; the two heavy ones are its answers
Fig. 1 Two lines on a square sheet and both of the folds the third axiom names for them. Each brings the first line onto the second; they are perpendicular to one another and they crease the paper in completely different places.

They are always perpendicular. That is not a coincidence of the example: the two bisectors of a pair of crossing lines are the internal and external ones, and a pair of angle bisectors is square by construction. The measurement checks it to machine precision on every input, and it has never been off.

So this is not a case of two nearly-identical answers where either would do. The two folds are as far apart in direction as two folds can be.

The parallel case, which is the exception

Two lines that do not meet have no angle between them and no pair of bisectors. The third axiom on parallel lines names exactly one fold: the midline, half way between them and parallel to both.

That is the only input on which the third axiom is single-valued, and it is a set of measure zero — two lines drawn at random are never parallel. It matters anyway, because the lines a folder actually works with are the sheet’s own edges and its previous creases, and those are parallel far more often than a random draw would suggest. A square has two pairs of parallel edges; a grid of creases is parallel families.

So the axiom’s ambiguity is at its worst on general inputs and vanishes on a large share of the inputs anybody uses, which is a second reason the counts below are about a distribution rather than about folding.

How often both are available

The sheet decides how often the ambiguity actually arises, because a fold that misses the paper is not a fold a folder can make.

How often the third axiom names two folds at onceRandom pairs of lines in a square sheet, put to the axiom that brings one line onto another. It has two solutions — the two angle bisectors, always perpendicular to each other — and the count is of how often both of them, one of them, or neither leaves a crease on the paper.the bar is how many of the inputs fall in each case4000 pairs of lines drawn in the sheet, with the same stream every time this is builtboth folds on the paper296574.1% — the axiom names a fold and does not choose itone on the paper103525.9% — the sheet makes the choice the axiom did notneither on the paper00.0% — the operation names no fold a folder can makethe two folds' midpoints are 0.32 sheets apart at the median and 0.89 at the widest, so the choice is not a small one
Fig. 2 Four thousand random pairs of lines drawn in a square sheet, put to the third axiom, and sorted by how many of its two folds leave a crease on the paper.

Both land on the paper 2,965 times of 4,000, one lands 1,035 times, and neither lands never. So three quarters of the time the axiom hands a folder a choice, and a quarter of the time the sheet makes the choice for them by putting one of the answers off the edge.

The midpoints of the two creases are a third of a sheet apart at the median and nearly a whole sheet at the widest. Nobody is going to fold one intending the other.

Which of the two a construction takes

There is a practical consequence for anything that computes with these, and it is the reason the multiplicity was noticed here at all.

A program handed an alignment has to return something. If it returns one fold it has made a choice the axiom did not make, and unless it says so the choice is invisible — the construction proceeds, the crease lands somewhere, and everything downstream is about one branch of a two-branched operation. If it returns both, everything downstream has to handle a set.

This collection returns both. The third axiom’s function hands back an array of two folds, or one where the lines are parallel and the only answer is the midline. What each axiom is worth counts what the operations reach, and the counting has to be over folds rather than over alignments, or the fifth axiom’s contribution is halved.

What one fold can refer to, and what two canThe set of points a folder can refer to, after nothing, after one fold and after two. Every axiom names points and lines that must already exist, so the reachable set is finite at every depth: four corners, then nine references, then several hundred. The faint lines are the folds the axioms specify; the marks are the crossings that land on the paper.the bare sheet4 references · 4 linesnothing has been foldedafter 1 fold9 references · 12 lineshalves, and nothing elseafter 2 folds565 references · 92 lineshalves, thirds, fifths — and worsea fold is an alignment, and an alignment needs something already on the paper to align565 references after 2 folds, and the count is finite however many folds are allowed
Fig. 3 The points two folds reach on a square. Every alignment that names two folds contributes both of them to this, and treating an axiom as single-valued would have produced a smaller set with no indication that anything was missing.

The fifth is worse

The third’s ambiguity is at least regular: two answers, always at right angles, and knowing that is most of what a folder needs.

The fifth axiom folds a point onto a line through another point — a point placed on a line while a crease passes through a named point. Geometrically it is the intersection of a circle with a line, so it has two solutions, or one at tangency, or none.

Over four thousand random inputs in a square: two solutions 3,009 times, none 991 times, and exactly one never — tangency is a measure-zero coincidence and a random draw does not find it.

And the two solutions are at any angle at all. Half a degree apart at the closest of four thousand, ninety degrees at the widest, sixty-eight at the median. So there is no rule of thumb here: two folds that might be almost the same or might be square, with nothing in the statement to say which is meant or how far apart they will be.

The fifth axiom's two answers, and how far apart they areRandom inputs to the axiom that brings a point onto a line by a crease through another point. It is a circle meeting a line, so it has two solutions or none, and the angle between the two is anything from almost nothing to a right angle.the bar is how many of the inputs fall in each case4000 inputs drawn in the sheet, with the same stream every time this is builttwo folds300975.2% — the crease line crosses the circle twiceone fold00.00% — tangency, which a random draw never meetsno fold99124.8% — the point is too far from the line to reachthe two folds are 0.6° apart at the closest of 3009 and 90° at the widest, with no rule saying which
Fig. 4 Four thousand random inputs to the fifth axiom, sorted by how many folds it names for each. Two, three thousand and nine times; none, nine hundred and ninety-one; exactly one, never.
The fifth axiom's two answers, and how far apart they areRandom inputs to the axiom that brings a point onto a line by a crease through another point. It is a circle meeting a line, so it has two solutions or none, and the angle between the two is anything from almost nothing to a right angle.the bar is how many of the inputs fall in each case4000 inputs drawn in the sheet, with the same stream every time this is builttwo folds300975.2% — the crease line crosses the circle twiceone fold00.00% — tangency, which a random draw never meetsno fold99124.8% — the point is too far from the line to reachthe two folds are 0.6° apart at the closest of 3009 and 90° at the widest, with no rule saying which
Fig. 5 The fifth is worse, drawn at three configurations: a point brought onto a line by a crease through another point. The construction is a circle meeting a line, so it names two folds, one fold or none, and which of the three is not a property of the axiom.

The nine hundred and ninety-one failures are the other end of the same geometry and they are already counted: the point is further from the line than the crease through the named point can reach, so the circle misses. Two answers or none, with the boundary between them a coincidence.

What the seven actually are

This changes what the list of seven is a list of, and the change is worth making explicitly.

An axiom is usually read as a fold specified by an alignment — hand it the alignment and get the crease. Read that way, an axiom is a function.

It is not a function. It is a relation: an alignment, and the set of folds satisfying it. That set has size nought, one, two or three depending on the axiom and the input, and only the first, second and fourth are single-valued for every input they accept.

How often the third axiom names two folds at onceRandom pairs of lines in a square sheet, put to the axiom that brings one line onto another. It has two solutions — the two angle bisectors, always perpendicular to each other — and the count is of how often both of them, one of them, or neither leaves a crease on the paper.the bar is how many of the inputs fall in each case8000 pairs of lines drawn in the sheet, with the same stream every time this is builtboth folds on the paper590873.8% — the axiom names a fold and does not choose itone on the paper209226.1% — the sheet makes the choice the axiom did notneither on the paper00.0% — the operation names no fold a folder can makethe two folds' midpoints are 0.33 sheets apart at the median and 0.96 at the widest, so the choice is not a small one
Fig. 6 What the seven actually are, from the branching side and at twice the sample: how often the third axiom names two folds rather than one. The share is not small and it does not depend on how hard the question is asked.

The enumeration that produces the number seven is an enumeration of alignments, not of folds. That is the right thing to enumerate — it is what makes the list complete — and it means the seven cannot be read off as seven constructions.

Counted properly the seven alignments name rather more than seven folds. The first, second and fourth name one apiece; the third names two where the lines meet and one where they are parallel; the fifth names two or none; the sixth up to three; the seventh one. So an inventory of folds specifiable in one step is not seven of anything, and the number seven is doing a different job — it is the count of ways two constraints can be spent, which is what makes the list provably complete.

Why the list stops at seven is the argument for completeness, and it is an argument about alignments throughout. Nothing in it is disturbed by an alignment having several answers; the list would still be complete if every one of them had a hundred.

The answer count is the degree

The essay sorts the seven into the single-valued ones with linear conditions and the multi-valued ones with curved conditions, and the sort is nearly right. Sharpened, it becomes an exact rule: an alignment names as many folds as the degree of the equation it produces.

Run the list. The first, second and fourth impose conditions that are linear in the fold line — through two points, the perpendicular bisector of two points, perpendicular to a line through a point — and a linear system has one solution. One fold each.

The third imposes an angle condition, which is quadratic, and names two. The fifth is a circle meeting a line, degree two, and names two. The sixth is the cubic, and names up to three. Every count matches its degree.

The seventh is the case that makes the rule better than the linear-versus-curved reading. It brings a point onto a line and is perpendicular to another line — one curved condition and one linear one — and it names exactly one fold. The reason is that the perpendicularity fixes the fold’s direction first, and with the direction fixed, placing a point on a line is one equation in one remaining unknown and is linear in it. A curved condition can be single-valued once something else has pinned down the freedom the curvature lived in.

So the rule is not about whether a condition is curved. It is about the degree of the system the two conditions form together, and the seven read off as 1, 1, 2, 1, 2, 3, 1.

Which says how many folds the seven really name

That list also answers the question the essay poses and leaves as a remark — how many folds are specifiable in one step, as against how many alignments there are.

On the measured distributions the count is not the sum of those degrees, because some solutions miss the paper. The third names two folds that both land three quarters of the time and one the rest, which averages 1.74 usable folds per input. The fifth names two three quarters of the time and none otherwise, averaging 1.50. The four single-valued alignments contribute one apiece.

Those six together average 7.25 usable folds per set of inputs, before the sixth axiom is counted at all. So the seven alignments already name more than seven folds, and the sixth — with up to three solutions of its own — pushes it higher.

The number seven is therefore not a count of folds and is not even close to one by accident. It is a count of ways to spend two constraints, which is what makes the list provably complete, and the fold count is a different and larger quantity that depends on the sheet.

The two ends of the same defect

Read together, the two under-determinations are one fact seen from opposite sides, and the fact is that an alignment is a condition rather than an instruction.

A condition on a fold line carves out a subset of the two-dimensional space of lines. Two independent conditions carve out an intersection, and an intersection of two curves in a plane is a finite set of points — usually more than one, sometimes empty, and only in special cases exactly one. Everything counted here is that generic behaviour showing through.

Seen that way, the surprise is not that the third and fifth axioms have two answers. It is that the first, second and fourth have exactly one, and they do because their conditions are linear rather than curved: a fold through two points is a line through two points, and two lines meet once. The axioms with multiple answers are the ones whose conditions involve a parabola or a circle, and those are precisely the ones that reach past the compass.

So the ambiguity and the power arrive together. An axiom that names one fold per alignment is an axiom whose conditions are linear, and linear conditions do not solve cubics.

What a folder does about it

In practice the ambiguity is resolved by the sheet, by convention, or by looking.

The sheet resolves a quarter of the third axiom’s cases outright, by putting one answer off the paper. That is the commonest resolution and it is invisible: a folder who has never seen the other answer does not know a choice was made.

Convention resolves most of the rest. The internal bisector is the one somebody drawing a diagram means, and it is the one that stays inside the region between the lines. Nothing in the axiom says so.

And looking resolves the fifth, which has no convention available because its two answers are not related by any symmetry. A folder given the alignment has to place the point on the line and see where the crease falls, twice, and pick.

The one axiom whose answers are truly interchangeable

There is a case where the two answers really do not matter, and separating it out is worth doing because it is the only one.

Two parallel lines have one bisector, the midline, and the third axiom is single-valued on them. That is not the interchangeable case; it is the case with no choice.

The interchangeable case is the third axiom on two lines meeting at a right angle. There the two bisectors are the two diagonals of the right angle, and they are related by the reflection that swaps the two given lines — so any construction symmetric in its two inputs gets the same answer either way, up to that symmetry. Every other angle breaks it: the internal bisector lies between the lines and the external one does not, and they do genuinely different things to the paper.

That is a narrow exception, and the reason to state it is that right angles are exactly what a square sheet’s edges provide. A folder working from the corners of the paper meets the interchangeable case far more often than a uniform draw suggests, which is one more reason the counts above are about a distribution nobody folds in.

Why this matters for the arithmetic

The cubic comes from the sixth axiom, and the connection between folding and root-finding runs through exactly this multiplicity.

A cubic has up to three real roots, and the sixth axiom has up to three solutions, and those are the same three: the fold that solves the cubic is the root, and an equation with three roots is an alignment satisfied by three folds. The multiplicity is not a defect in the statement of the axiom. It is the arithmetic showing through.

Axiom 6 is a common tangentA fold that carries a point onto a line is tangent to the parabola with that point as focus and that line as directrix. Axiom 6 does it twice at once, so it asks for a line tangent to two parabolas — and two parabolas have three common tangents, which is why one fold solves a cubic and a compass cannot.the cubicx³ − 2xits roots-1.4142141.4142142 real common tangents1 of the three are complexand the fold gives cos 2π/7each curve is the set of folds that puts one point on its line; a line touching both does the two at oncea compass intersects circles and gets two answers; a fold touches parabolas and gets up to three
Fig. 7 The sixth axiom as a root-finder: each of the cubic’s real roots is a fold tangent to both parabolas, and three roots means three folds satisfying one alignment.

So the same fact is a nuisance for a folder and the entire point for a mathematician. An axiom that named exactly one fold per alignment could not solve a cubic, because a cubic does not have exactly one root.

How often the third axiom names two folds at onceRandom pairs of lines in a square sheet, put to the axiom that brings one line onto another. It has two solutions — the two angle bisectors, always perpendicular to each other — and the count is of how often both of them, one of them, or neither leaves a crease on the paper.the bar is how many of the inputs fall in each case1500 pairs of lines drawn in the sheet, with the same stream every time this is builtboth folds on the paper110473.6% — the axiom names a fold and does not choose itone on the paper39626.4% — the sheet makes the choice the axiom did notneither on the paper00.0% — the operation names no fold a folder can makethe two folds' midpoints are 0.34 sheets apart at the median and 0.89 at the widest, so the choice is not a small one
Fig. 8 The third axiom’s census at fewer inputs. The proportions move by a fraction of a point and nothing about the shape changes, which is what a count over four thousand draws of a fixed distribution should do.

Where the ambiguity has already been paid for

This collection computes with the axioms in two places, and the two handle the multiplicity differently for reasons worth separating.

The reachable set takes every solution of every alignment. That is the right choice there, because the question is which points a folder can reach and a fold that reaches a point is a fold whether or not another fold satisfies the same alignment. Dropping one branch would have shrunk the set by a quarter with nothing to say it had happened.

The constructions — trisection, the cube root, an exact seventh — name their branch. Each is a sequence of specific folds arriving at a specific point, and a construction that said bring this line onto that one without saying which bisector would be a procedure a reader could follow to the wrong answer half the time. So the diagrams show the crease and the text names the alignment, and the crease is what disambiguates.

That division is the standard one in the literature too, and it is why the ambiguity is invisible: nobody meets it, because every published construction has already resolved it by drawing the answer.

What is being counted, and what is not

Two limits on these numbers.

They are over inputs drawn uniformly in a square, which is a stated distribution and not a natural one. A folder does not choose lines at random; they choose lines that are already on the paper, which are the edges and previous creases, and those are far from uniform. How far from the nearest reference measures the real population and it is nothing like this one.

And a fold that lands on the paper is not the same as a fold anybody can make. The crease has to be reachable by actually bringing the alignment together, which for a fold near the edge of the sheet means holding very little paper. Closer than a crease is wide is the account of where that limit sits, and it is a limit these counts do not apply.

What the numbers do establish is comparative and robust to both. The third axiom’s ambiguity is available on most inputs, its two answers are perpendicular, and the fifth’s are anywhere — and none of that depends on which distribution the inputs were drawn from.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

What links here

Every essay whose body links to this one.

The objects this essay names

Each one links to every other essay that touches it.

AmbiguityAngle bisectorAxiomConstructionFold lineThe Huzita–Hatori axiomsReference pointSheet shape