Flat-folding

An alternating sum of angles

Kawasaki's condition says the sectors round a vertex alternate to a straight angle. A glued band has no vertices and obeys a condition of exactly the same shape: the crease angles have to alternate to a multiple of a straight angle. Two different quantities, two different sheets, one arithmetic — and in both cases what is being said is that a product of reflections came back the right way.

Assumes Closure is not the identity and Two conditions at a point.

Two conditions in this subject are alternating sums of angles, and they are about completely different objects.

The first is Kawasaki’s. Round an interior vertex the sectors between consecutive creases, taken alternately positive and negative, have to add to nought — equivalently, the odd sectors and the even sectors each add to a straight angle. It is a statement about one point of the paper, it is the oldest condition the subject has, and every folder meets it in the first week.

The second is about a sheet with no interior vertices at all. On a strip of paper glued into a band, the crease angles, taken alternately positive and negative, have to add to a multiple of a straight angle. It is a statement about the whole sheet, it constrains the drawing before a single crease is placed anywhere, and it has no vertex in it.

That two conditions of the same shape govern two such different situations is not a coincidence, and the common cause is worth having: both are saying that a product of reflections came back as the right kind of motion.

What the condition is

A band’s creases run from one edge of the strip to the other. Each has an angle to the strip’s long direction — ninety degrees for a crease square across, sixty for one slanting forwards, a hundred and twenty for one slanting back.

The closure condition says the reflections in those creases, composed in order, have to equal the map that glues the band’s two ends together. That equation has a linear part and a translation part, and they behave differently.

The linear part is a two-by-two matrix and it depends on the crease angles and nothing else. Reflection in a line at angle ϕ\phi has a linear part determined by ϕ\phi; where the line sits enters only the translation. So composing kk reflections gives a linear part determined by

ϕ1ϕ2+ϕ3±ϕk\phi_1 - \phi_2 + \phi_3 - \cdots \pm \phi_k

and by nothing else about the drawing.

For a Möbius band the gluing map’s linear part is a reflection in the band’s own axis, at angle nought. So the condition is that the alternating sum is a multiple of a straight angle.

Which pairs of crease angles a Möbius band admitsThe first two crease angles of a three-crease Möbius band, with a mark at every pair for which a third angle exists. The composition's linear part is a reflection in the direction of the alternating sum of the angles, so the third is determined by the first two and the admissible set is a curve rather than a region: almost every triple of angles folds nothing at any length.the angles that admit a thirdφ₁ − φ₂ + φ₃ a multiple of a straight angle30°30°60°60°90°90°120°120°150°150°60°, 120°the first crease's angle, against the secondevery other pair of angles folds nothing,at any length and any positions
Fig. 1 For a three-crease Möbius band, the first two angles plotted against each other with a mark wherever a third exists that satisfies the condition. The third angle is determined by the first two, so the admissible set is a curve.

Decided before anything is placed

The practical force of the condition is when it applies.

Every other constraint on a band involves where the creases are: whether they fit inside the strip, whether they are in order, whether they cross each other, whether the translation comes out right. All of those need positions.

The alternating sum needs none. Given three angles, the linear part is already determined, and if it does not match, no arrangement of those creases at those angles on a strip of any length will ever close. The drawing can be abandoned before it is drawn.

What the reflections compose to on a Möbius bandThe 3 creases of the band, each a reflection, composed in order — and beside it the gluing map the composition has to equal. On a disc that map is the identity and the condition reads "the composition is the identity", which is the only form of it anybody states. Here the two differ by 4.00e+0 of the band's own width.the composition, and what it has to equal3 reflections, in order[ -1.000 0 ][ 0 1.000 ]+ ( 2.000, 0 )=?the gluing map of a Möbius band[ 1.000 0 ][ 0 -1.000 ]+ ( -2.000, 1.000 )they differ by 4.000 of a width, so it does notand both turn the paper the same way, so the parity is righton a disc the right-hand side is the identity, which is why nobody writes it down
Fig. 2 Three creases square across the strip. The alternating sum of three right angles is a right angle, the gluing map wants nought, and the two linear parts differ — visibly, in the four numbers. Where the creases are cannot enter, because the positions appear only in the translation.

That is an unusual shape for a condition in this subject. Almost everything else here — the letters, the layer order, the packing — is a search over arrangements. This one refuses whole families of arrangements without looking at one.

The same arithmetic at a vertex

Kawasaki’s condition is the same statement about a different loop.

Round an interior vertex, the panels form a cycle. Walking round it and composing the reflection in each crease returns a rotation, and the rotation is by twice the alternating sum of the sector angles between consecutive creases. The paper has to come back where it started, so the rotation has to be nothing, so the alternating sum has to be nought — which is Kawasaki, written as a composition.

A vertex that folds flatFour creases at one point, with the sectors between them measured and both flat-folding conditions evaluated. Kawasaki constrains the angles and Maekawa constrains the assignment; a vertex needs both, and they are independent of one another.VMMM70°110°110°70°Kawasaki70° + 110° = 180°110° + 70° = 180°both 180° — satisfiedMaekawa3 mountains, 1 valleysdifference 2exactly 2 — satisfiedangles sum to 360°which is what a flat sheet requiresmountainvalley
Fig. 3 A four-crease vertex with its sectors measured and the alternating sums printed. The condition that the two sums agree is the condition that the reflections round the vertex compose to the identity, which is the closure condition on the smallest loop a sheet with vertices has.

So the two conditions differ in three ways and agree in the fourth.

They differ in which loop: a vertex’s loop is a circle round one point; a band’s is a circuit of the whole sheet.

They differ in which angles: a vertex’s condition reads the sectors between the creases; a band’s reads the directions of the creases.

They differ in what the composition has to equal: at a vertex, the identity, because the walk returns to the same paper; on a band, the gluing map, because it does not.

And they agree in why: both are the statement that a composed product of reflections is the motion the sheet demands, and in both cases the linear part of that product depends on an alternating sum and the positions do not enter it.

Why the sum alternates

The alternation is not a convention, and it is worth seeing where it comes from, because it is the same in both cases.

Composing two reflections in lines at angles α\alpha and β\beta gives a rotation by 2(αβ)2(\alpha - \beta). The minus sign is not chosen: reflections do not commute, and the rotation their product produces turns from the second line towards the first. Composing four gives a rotation by 2(αβ+γδ)2(\alpha - \beta + \gamma - \delta) — the signs alternating because the products pair up.

An odd number of reflections composes to a reflection rather than a rotation, in a line at the alternating sum itself rather than at twice it. That is why a Möbius band’s condition reads the alternating sum is a multiple of a straight angle rather than twice it is, and why a cylinder’s, which needs an even count, reads as a condition on twice the sum.

The alternation is therefore a fact about reflections and not about paper, and it shows up in every condition of this subject that comes from composing them.

What the admissible set looks like

One equation among three angles leaves a two-dimensional family, and inside the square of possible first-and-second angles it is a curve.

That has a consequence worth stating plainly: a triple of angles chosen at random folds nothing. Not usually nothing — nothing, with probability one, because a curve has no area. Whatever length the strip is given and wherever the creases are put, the linear parts do not match, and the mismatch is not small: it is a whole reflection out.

3 creases on a Möbius bandA rectangular strip of paper with 3 creases across it and its two ends glued into a Möbius band. The arrows on the left and right edges show which way round the gluing carries one onto the other; on a Möbius band they point in opposite directions, which is the whole of the difference between the two sheets. The strip has 3 panels and no interior vertex at all, so every vertex condition in the subject is satisfied here without deciding anything.3 creases on a Möbius bandthe panels take two coloursseamthe same seam123the right edge onto the left, turned over3 creases, 3 panelsinterior vertices: 0two-coloursthe reflections closeand turn the paper the right waymountainvalleyraw edge
Fig. 4 One point of the admissible curve away from the equilateral one: seventy, a hundred and forty and seventy degrees, whose alternating sum is nought. It folds, and it needs a strip nearly two and three-quarter times its own width to do it.
The shortest 70/140/70 bandThe width the solved creases need, against the length of the strip they are solved on. The closure holds at every length — the algebra is linear and always has a solution — and what runs out is room: below 2.7475 widths the creases the solution asks for do not fit between the ends in order. The two lines cross at exactly that ratio.what the creases need, against what the strip has2.74748the stripwhat it needs0.50.51.01.01.51.52.02.02.52.53.03.0lengths in widths of the stripthe shortest strip that holds them is 2.747477 of its own width
Fig. 5 The same triple, with the width the solved creases need against the length they are solved on. The closure holds at every length here too; what decides the shortest strip is the drawing running out of room, and this triple runs out much later than the equilateral one does.

Angles first, then positions

Once the alternating sum is right, the rest of the condition is two linear equations in the crease positions, which is a solve rather than a search.

That two-stage structure — a discrete-looking condition on the angles, then a linear condition on the positions — is what makes bands tractable in a subject where almost nothing is. It is also what makes the count of admissible drawings a strange quantity: there is a curve of admissible angle triples, and above each point of that curve, a line of admissible position triples, and a half-line of admissible lengths.

What the reflections compose to on a Möbius bandThe 3 creases of the band, each a reflection, composed in order — and beside it the gluing map the composition has to equal. On a disc that map is the identity and the condition reads "the composition is the identity", which is the only form of it anybody states. Here the two differ by 6.66e-16 of the band's own width.the composition, and what it has to equal3 reflections, in order[ 1.000 0 ][ 0 -1.000 ]+ ( -1.732, 1.000 )=?the gluing map of a Möbius band[ 1.000 0 ][ 0 -1.000 ]+ ( -1.732, 1.000 )they agree to rounding, so the band foldsand both turn the paper the same way, so the parity is righton a disc the right-hand side is the identity, which is why nobody writes it down
Fig. 6 The composition of the equilateral band’s three reflections against the map it has to equal, with both sides written out. The linear parts agree because the angles satisfy the alternating sum; the translations agree because the positions were solved to make them.

The ranking the condition does not do

The alternating sum says which triples are admissible. It says nothing at all about which is best, and the difference between them is large.

The paper each Möbius band needsThe nine cheapest triples of crease angles that a three-crease Möbius band admits, with the shortest strip each one can be folded on, in widths. The equilateral triple is the shortest at √3 = 1.732051, and the next needs about eleven per cent more paper.the strip each admissible triple needs60° · 120° · 60°1.7321.7321 widths120° · 60° · 120°1.7321.7321 widths70° · 140° · 70°2.7472.7475 widths110° · 40° · 110°2.7472.7475 widths50° · 120° · 70°2.7472.7475 widths60° · 130° · 70°2.7472.7475 widths70° · 120° · 50°2.7472.7475 widths70° · 130° · 60°2.7472.7475 widths110° · 50° · 120°2.7472.7475 widths√3 is 1.732051, and the equilateral band comes out at 1.732057
Fig. 7 The nine cheapest admissible triples, ranked by the shortest strip each needs. The equilateral one is first at √3 and the next needs eleven per cent more paper; most of the curve needs half as much again.

That ranking comes from the fitting rather than the closing, and it is a reminder that the conditions of this subject stack rather than combine. The alternating sum is an equation. The positions are an equation. Fitting is an inequality, and it is the inequality that decides which of the infinitely many closing drawings a person would actually make.

A worked instance in degrees

Take the condition at face value and try three angles by hand.

Sixty, a hundred and twenty, sixty: 60120+60=060 - 120 + 60 = 0. Admissible.

Forty-five, ninety, forty-five: 4590+45=045 - 90 + 45 = 0. Admissible.

Seventy, a hundred and ten, seventy: 70110+70=3070 - 110 + 70 = 30. Not a multiple of a straight angle, so not admissible — and no length of strip and no placement of those three creases will ever produce a Möbius band. The mismatch is a reflection thirty degrees out of place, and it is thirty degrees out of place at every length.

Ninety, ninety, ninety: 9090+90=9090 - 90 + 90 = 90. Not admissible, which is the square-creased case and the reason no band creased straight across the strip folds at any odd count.

Thirty, sixty, thirty: 3060+30=030 - 60 + 30 = 0. Admissible, and it needs a long strip, because a crease at thirty degrees spans nearly two widths along the band and three of them have to fit in order.

The arithmetic is that easy, and it is the whole of the first stage. Anybody with a protractor and a strip can decide in ten seconds whether a proposed set of angles has any chance, which is not a sentence that can be written about many conditions in this subject.

The second angle is free and the third is not

There is a small asymmetry in the condition that is easy to misread.

Given the first angle, the second may be anything; given both, the third is determined up to a straight angle. So the admissible set is parameterised by two free choices and a determined third, which is why the picture above is a plot of the first two with a mark wherever the third exists.

The mark is present at almost every pair, because some third angle always exists — the equation ϕ3=ϕ2ϕ1\phi_3 = \phi_2 - \phi_1 always has a solution. What restricts the picture is that the third angle has to be an angle a crease can actually have: a crease at nought or a hundred and eighty degrees runs along the strip rather than across it, and does not divide the band into panels at all.

So the admissible region is the whole square minus two thin strips near its edges, and the curve the earlier section spoke of is the curve in the space of triples rather than in the space of pairs. Both descriptions are right and they are descriptions of different spaces, which is worth being careful about: the set of admissible triples is two-dimensional inside a three-dimensional space, which is measure zero there, and its shadow on the space of first-and-second angles is almost everything.

That distinction is exactly the one the genericity argument turns on, and getting it the wrong way round makes a band look far easier to fold than it is.

What happens at four creases and beyond

The essay has been about three creases because three is the smallest odd number that can work. The condition generalises without changing shape and the consequences shift.

At five creases the alternating sum is ϕ1ϕ2+ϕ3ϕ4+ϕ5\phi_1 - \phi_2 + \phi_3 - \phi_4 + \phi_5, and there are four free angles with the fifth determined. The admissible set is bigger and the solve for positions is still two equations, now in five unknowns, so the solution set is three-dimensional and there is real freedom in where the creases go. Bands with five creases fold on shorter strips than the arithmetic might suggest, because the extra freedom can be spent on fitting.

At even counts on a Möbius band, nothing works, and it is refused before the angles are reached: the parity of the composition is wrong whatever the angles are.

On a cylinder the roles swap. Even counts are the ones that can work; the alternating sum condition becomes a condition on a rotation rather than on a reflection; and two parallel creases square across the strip satisfy it trivially, which is why a paper tube flattens with two creases along its length and a tube of any circumference will do.

The general statement covering all of these is one sentence: the composed linear part, determined by the alternating sum, has to equal the linear part of the sheet’s own identification. Everything else is which sheet and how many creases.

Why nobody states it about vertices this way

Kawasaki’s condition is normally stated as the alternating sum of the sectors is nought, or equivalently as the odd sectors and the even sectors each add to a straight angle, and it is normally proved by an argument about the paper closing up rather than by composing reflections.

The reflection proof is not better and it is more general, which is the only reason to prefer it here. It says: walk round the vertex, compose the reflections, require the identity; the linear part of the composition is a rotation by twice the alternating sum of the sectors, so the sum must be a multiple of a straight angle; and the sectors are positive and add to a full turn, which pins it to nought.

Written that way, the condition on a band is the same proof with the vertex’s loop replaced by the band’s, and the identity replaced by the gluing map. Written the usual way, the two look unrelated, and the second one has to be discovered rather than derived.

That is most of the argument for keeping the general form around even where the special case is enough: the general form is what makes a second instance recognisable when it turns up.

The condition, checked

The alternating sum is asserted rather than trusted, and the assertion has a case it must reject.

Every band drawn here has its composition computed and compared against the map its own gluing demands, and the comparison returns a distance in widths of the strip rather than a verdict. A triple whose alternating sum is right and whose positions were solved reads nought to rounding. A triple whose alternating sum is thirty degrees out is asked for and refused, and the refusal is checked: if the machinery ever reported seventy, a hundred and ten and seventy as folding, the figures would stop being drawn.

That is the shape of assertion this collection prefers. A check that has never rejected anything is a comment about the code rather than a statement about the mathematics, and a condition this cheap to state deserves at least one case that it correctly declines.

Where the condition is silent

Three things it does not say, each of which has caught somebody.

It says nothing about which sheet. A cylinder’s gluing map has a linear part that is the identity, so its condition on an even number of creases is that the alternating sum is a multiple of a straight angle and twice it is a multiple of a full turn — which for parallel creases is automatic. The condition takes a different form on the two sheets and it is the same equation.

It says nothing about the letters. Mountain and valley never appear above. The composition treats both alike, because folding along a line reflects the paper across it whichever way the fold goes, and the whole of this argument is about where the paper ends up rather than which way it went.

It says nothing about a sheet with vertices. A band’s creases meet nothing, so the sheet has exactly one loop and one equation. Add a vertex and there are as many loops as the panel graph has independent cycles, and requiring all of them is the full flat-foldability problem, which is hard.

Which bands fold, on each of the two sheetsFor a cylinder and for a Möbius band, whether a strip with that many creases across it has a flat folded state. A cylinder needs an even number and a Möbius band an odd one, and the reason is that a composition of reflections turns the paper over when there are an odd number of them while the two gluing maps differ in exactly that.which bands foldcreases across the strip123456nofoldsnofoldsnofoldsfoldsnofoldsnofoldsnocylinderMöbius bandthe gluing map of a cylinder is a slide and of a Möbius band a slide with a flipand a composition of k reflections turns the paper over exactly when k is odd
Fig. 8 Both gluings at six crease counts, with the parity refusing half of them before any angle is looked at. The alternating sum is the condition on what survives, and the fitting is the condition on what survives that.

An angle is a direction, not an orientation

One more piece of care, because it is where a sign gets lost.

A crease is a line, and a line has a direction only up to reversal: the crease running at sixty degrees is the same crease as the one running at two hundred and forty. So the angles in the alternating sum are defined modulo a straight angle, not modulo a full turn.

That is why the condition reads a multiple of a straight angle rather than nought, and it is why the admissible triples come in families: sixty, a hundred and twenty, sixty is the same drawing as sixty, a hundred and twenty, two hundred and forty, and the sum changes by a straight angle between the two ways of writing it.

The consequence for computation is small and the consequence for reading the condition is not. A reader who fixes each angle in the range from nought to a hundred and eighty — which is the natural thing to do, since a crease crossing the strip has an angle in that range — will find the alternating sum of three of them lying between minus a hundred and eighty and plus three hundred and sixty, and the condition admits nought, a hundred and eighty, and minus a hundred and eighty as the same answer.

Getting that wrong makes a third of the admissible triples invisible.

Two conditions on one drawing

A last placement, since the essay has two alternating sums in it and the collection has more.

Kawasaki’s condition at a vertex and the band’s condition on its crease directions are the two alternating sums here. The big-little-big lemma reads angles too and is not an alternating sum — it is a comparison, picking out the strictly smallest sector, and it says nothing at all when no sector is strictly smallest.

So of the subject’s three angle conditions, two are alternating sums arising from compositions of reflections and one is not, and the odd one out is the one that can be vacuous.

What is worth carrying

Three sentences.

A composition of reflections has a linear part that depends only on the directions of the lines, through an alternating sum, and a translation that depends on where they are.

A closed walk on a sheet has to compose to the motion that walk’s own identification demands, which on a disc is the identity and on a glued sheet is not.

Put those together and every alternating-sum condition in this subject is the same condition asked about a different loop — which is why Kawasaki’s, discovered at a vertex, and a band’s, discovered on a sheet with no vertices at all, are written with the same arithmetic and could hardly look less alike.

What this makes readable

Essays that name this one as a prerequisite.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

What links here

Every essay whose body links to this one.

The objects this essay names

Each one links to every other essay that touches it.

ClosureFlat-foldabilityGenericityGluingKawasaki's theoremThe Möbius bandNecessary conditionReflectionSector angles