Concept

Optimisation — where it appears

Searching for the best member of a family rather than deriving it. Most packing questions in this subject are settled by search, so the answers quoted are the best anything has found rather than proved optima, and comparisons need equal effort on both sides.

Named by 18 essays across 5 fields — each of them below, with the objects they name alongside it.

leglegarmarmheadthe checkclosest approach 0.0000no overlap — the packing is validcircles use 71% of the sheetthe rest becomes the bodyefficiency is how much of thesquare the circles can claim,and it is an open problemthe dashed skeleton is the subject; the circles are what it costs

Packing is the hard part

Once a subject is a set of circles, designing the model is fitting them into a square. That step has no general algorithm, no known optimum, and it is where every remaining difficulty in origami design now sits.

design · Circle packing
2 discs53.9%r = 0.29293 discs61.0%r = 0.25434 discs78.5%r = 0.25005 discs67.3%r = 0.20716 discs66.3%r = 0.18767 discs66.9%r = 0.17448 discs72.8%r = 0.17029 discs78.5%r = 0.1667hexagonal density 90.69%every bar is the best a seeded search found, not a proved optimum —which is the honest state of the problem for all but the first few values of n

How much paper is wasted

The efficiency of a design is the fraction of the sheet its flaps can claim, and for almost every number of flaps nobody knows the best possible value. The bars in these figures are the best a search could find, which is not the same thing.

design · Circle packing
6 creases, 7 segments, assignment MVMVMVDoes it fold flat?at most 5,040 orderings, and it may stop earlyyesas far as the first legal oneHow many ways?every one of them, because the last is as likely as the first15,040 orderingsWhat are they?the same search, paying a second time for what it keeps1 stackings, written out5,040 orderings, and the answer as wellCan a machine make it?a different search, over sequences of folds rather than over stackingsno1,275 statesthe four are not four difficulties of one problem — they are four problemsthe cost is work rather than time — a clock reading would differ on every build

Four questions about one sheet

Deciding, counting, listing and optimising are not four difficulties of one problem. They are four problems, and folding is the subject that proves it: a ruled map is trivial to decide and unsolved to count, while a general crease pattern is the other way round.

complexity · Hardness of folding
discsfoundproved bestshort by20.292880.292890.00%30.254310.254330.01%40.250000.25000matched50.207050.207110.03%60.187580.187680.05%70.174360.174460.06%80.170220.170540.19%90.166670.16667matchedworst shortfall 0.19% of the radius, at 8 discsthe search never consults the published values, so the comparison measures the searchbeyond nine discs there is nothing to compare against, because nothing has been proved

Getting close instead of getting it right

When the best answer is out of reach the question stops being what it is and becomes how much is lost. For packing discs into a square the loss is measurable: a seeded search in this repository comes within a fifth of a percent of the best radius anybody has proved, and proves nothing.

complexity · Circle packing
quadrilateralconvexmolecule builtpentagonconvexmolecule builtL, one reflex cornerone reflex cornerconstruction refusedthe polygon admits a shrinkingdart, one reflex cornerone reflex cornerconstruction refusedthe polygon admits a shrinkinga convex polygon shrinks inward and stays a polygon; a reflex corner is a wall the shrink runs intoso a non-convex region is split into convex pieces first, and choosing the split is a searchwhich is where a construction that always works hands the difficulty to whatever comes before it

The molecule that does not exist

The universal molecule fills any convex polygon, always, which is what makes it the part of the tree method with no special cases. Hand it a reflex corner and it does not produce a worse pattern — it produces nothing, and the difficulty moves backwards to whoever chose the polygons.

design · Molecules
flapsfree search4×4 grid8×8 grid30.25430.2500 −1.7%0.2500 −1.7%40.25000.2500 −0.0%0.2500 −0.0%50.20710.1768 −14.6%0.1768 −14.6%60.18760.1250 −33.4%0.1398 −25.5%the 6-flap case on the finest lattice here is one of 3.25e+8 arrangements, and the bound settles all of themthe free optimum is unknown for most of these counts and the lattice optimum is known for all of thema finer lattice costs less and asks for more creases, which is the trade a designer actually makes

What the grid settles

Box pleating is usually defended as a trade: give up efficiency, buy creases that land where they should. There is a second thing it buys and nobody quotes it — on a lattice the best possible packing is a finite question with an answer, while off the lattice nobody knows the best packing of six circles in a square and probably never will.

design · Box pleating
42:3:4:363:4:6:583:4:6:5125:7:11:8165:7:11:8248:11:17:13each limb roundedthe best whole numbershow wrong the worst limb isgrid units across the longest limbthe numbers under the axis are the best whole-number limbs at that resolution

Spelling a tree on a grid

Box pleating asks every limb of a design to be a whole number of grid squares, which sounds like rounding and is not. Rounding each limb to its own nearest whole number is one way to choose the numbers, and at most resolutions it is not the best way — the best whole-number version of a subject is often a coarser one, with fewer squares and a shape twice as close.

design · Box pleating
0.287267creases in the moleculewhere the corner sits7 creases6 creasesat the marked shape three of the polygon's edges vanish at the same instant, and either side of it they vanish one at a time

The skeleton changes its mind

The universal molecule fills any convex polygon, always, which is what makes it the part of the tree method with no special cases. It does not fill it continuously. Slide one corner along its edge and the number of creases in the molecule sits at six, jumps, and sits at seven — so two designs a hairsbreadth apart have crease patterns that are not small variations on one another.

design · Molecules
6 flaps at radius 0.1875883 contact graphs among the runs that agree about itone run5 contacts · 5 against the paper's edgeanother run4 contacts · 5 against the paper's edge

Two packings, one radius

A packing search reports a number, and the number is not the design. What a crease pattern is built from is the graph of which discs touch which — and at five and six flaps, runs of the same search that agree about the best radius to four decimal places come back with contact graphs that are provably not the same graph. The answer an optimiser gives has not determined the pattern it is supposed to have found.

design · Circle packing
every rounding of the bird on 12 grids, by its error and its sizeopen dots: every rounding; filled: the frontier; ringed: a nearest rounding; level line: the tree as drawn0.2400.2600.28001020304050worst limb's error, per centsize of the model16910106141075allowed 12% error: 14 units, 4 14 7 7 12, size 0.2765

The grid belongs to the subject

Rounding a subject's limbs to whole grid units trades shape for size, and on any one grid the cheap-direction rounding is the largest. Put every rounding on every grid from three to sixteen units side by side and only a handful are worth having. For the bird, nine of 121 roundings are beaten by nothing on both counts; they come from seven grids, starting with the exact spelling on sixteen and buying size at about a quarter of a per cent for each point of worst-limb error. Eight, twelve, eleven, four and three units contribute nothing — every rounding on them is beaten by one on another grid. For the lizard, eight and twelve are on the frontier and six, ten and fourteen are not. No grid is good in general; a grid is good for a subject.

design · Uniaxial bases
fins of several lengths with a lumen kept clear down the middlethe diagonal is the most fins the circumference allows at each radius; the staircase is what the fins achieveradius, axis to wallfree lumenlumen radius 0.40R: 16% of the cross-sectionfins of 3 lengths hold 72.0% of the ceilinga lumen out to 0.25R would have cost nothingthe most any lining could hold now: 84.0%

A lumen costs nothing until it does

A tube lined with radial fins of m lengths holds at best m ⁄ (m + 1) of the most surface its sheet could carry, with the fins' tips on equally spaced rings. A tube also has to carry something down its middle. Keep a central lumen of radius ρR clear and the best lining puts its first ring of tips at the lumen and spaces the rest evenly to the wall, holding 2ρ(1 − ρ) + (1 − ρ)²(m − 1) ⁄ m of the ceiling — until the lumen is smaller than R ⁄ (m + 1), where it costs nothing at all, because the fins' own optimum already leaves that much empty. Past it, each further unit of lumen costs surface at a rate rising from nothing towards one. With unlimited lengths the frontier is the straight line 1 − ρ²: the bend is the price of having few lengths, and the free lumen is the wedge they wasted.

biology · Surface in a volume
the most surface a lining can hold for each lumen, and the lumen that surface needsthe straight line is the demand; each dot is a lining that holds what its own lumen can supply00.2500.5000.750100.2000.4000.6000.8001share of the cross-section given to the lumenshare of the ceiling the fins hold1 length2 lengths3 lengths10 lengthsunlimitedleft of its dot a lining would hold more than its lumen can supply; right of it, the lumen is wider than its surface needs

Supply decides whether lengths pay

A tube lined with fins has a frontier of surface against the lumen left down its middle, and a lining that must supply its own surface needs a lumen that grows with the surface. The two meet at one point per number of fin lengths. When a channel is narrow for what it serves, the meeting is on the flat stretch and supply costs nothing; when it is wide, every lining meets near the full lumen, and the lengths that were worth half again are worth under one per cent.

biology · Surface in a volume
the surface a supplied lining holds when its supply has to reacheach unit of surface at radius r needs a channel 1 + λ(r − ρ) times as wide as at the lumen's edge00.2500.5000.7501-2-101log₁₀ of the channel's width per unit of surface, in sheet thicknessesshare of the ceiling the fins holdone lengthunlimited lengthsthe same, reach freethe upright line is the channel of a fifth of a sheet per unit of surface; its dot is the unlimited lining there

Reach taxes the extra lengths

A tube's fin lining that must supply its own surface was priced with a channel of the same width for every unit of surface, wherever it stood. Charge instead for how far the supply has to carry, and the extra lengths of fin — which multiply toward the wall — pay more for each unit of surface than a single length does. Where supply was cheap they are worth half again rather than two thirds; the passage to lengths buying nothing moves to channels half as wide; and where supply was dear, nothing changes at all, because a thin ring has no reach inside it.

biology · Surface in a volume
the hexagon: 66.67 per cent at 60°, losing 0.448 points a degreedashed: the slope 2n tan²(π/n) ⁄ 9√3 a radian, either way; below, the inscribed circle59616365675256606468apex angle, degrees (60 is equilateral)share of the sheet, per centcircle

The worst angle sets the price

On a triangle of paper that is nearly equilateral, the largest regular hexagon loses 0.448 percentage points of the sheet for every degree the triangle is out of true, the nonagon 0.267 and the dodecagon 0.193. Those rates were measured. They have a closed form, 2n tan²(π/n) / 9√3 a radian, and it depends only on the worst of the triangle's three angles, whatever its shape. Rate times sides falls to 2π² / 9√3, and the window in which each polygon beats the circle shrinks as ninety degrees over its number of sides.

construction · Optimal constructions
one supply bill, written per unit of surface and as a branching tree3 lengths of fin at a channel of 1 per unit of surface, reach costing λ = 200.2500.5000.75010.8000.9001radius, from the lumen's edge to the wallextra channel at each radiuseach unit for its own reacharea 0.1170a tree sized to its flowarea 0.1170ticks on the axis are the rings of fin tips; the tree's channel steps down at each, the per-unit charge steps up

A shared supply is the same bill

A tube's fin lining charged for how far its supply has to carry was expected to do better under a supply that branches, one vessel running out along each fin and feeding everything it passes. It does not, and it cannot: with channels sized to the flow they carry, the per-unit charge and every branching tree are the same integral. Sharing pays only when a channel's width grows more slowly than its flow, as Murray's and Poiseuille's vessels do, and then branching buys back exactly what those economies would otherwise have charged, to within a fifth of a point.

biology · Surface in a volume
the worst strain straight tucks leave, against the number of starts placed for straindots: the placement's own worst strain; dashed: I² ⁄ 8m², with I = ∫ √(sin s ⁄ s) ds over the cap-5-4-3-2-1starts, on a doubling scalelog₁₀ of the worst strain2481632the dialled cap: 90°I = 1.464small dots: caps of 30° and 150°every doubling of the starts divides the worst strain by four, on every cap

A start is worth an inverse square

Straight tucks gathering a flat disc into a cap leave a worst strain that falls as the starts multiply, and every essay on them counted starts without saying what one buys. It buys an inverse square. A chord of the hiding curve misses it by its width squared times the curve's bend over eight, so starts placed for strain leave a worst strain of I² ⁄ 8m², with I one integral of the cap's shape — 1.464 for a hemisphere. A paper that gives ε therefore needs about I ⁄ √(8ε) starts, a tenth of the give costs three times the starts, and letting the hiding cross the curve saves exactly a factor of √2. The same argument says why the starts spread outward, and by how much.

material · Developability
the formula, the fitted polygons, and the two edges of the windowsolid: the one-line share, where the polygon keeps its base; dots: fitted; lower curve: the inscribed circle545658606264664550556065707580apex angle, degrees (60 is equilateral)share of the sheet, per cent

The window has an exact edge

How far an isosceles triangle may stray from equilateral before its largest regular hexagon falls behind its inscribed circle was measured — 15.6 degrees closing the apex, 19.1 opening it — and estimated to first order as the polygon's lead over its rate. Neither number needs measuring. The fitting problem has three sides and three unknowns, so its bound is an equality, the polygon keeps a side on the base, and its share is one line. That line carries the same factor as the circle's, so the circle's own loss cancels out of the comparison entirely, and each edge of the window is an angle in closed form. The opening half is wider because opening the apex lengthens the perimeter. And the window does not shrink as ninety degrees over the sides, as the first-order estimate says, but as (2 − √2)·180° over them — about 105 — because the corner's reach bends back as fast as it rises.

construction · Optimal constructions
where the hexagon beats the circle, in the plane of a triangle's two angle errorsxy10°the exact edge, fitted in 72 directionsthe first-order window, 13.9° of worst errorcorners: one angle up, one down, 21.8°isosceles, apex closing: 15.6°isosceles, apex opening: 19.1°

Two sides at sixty are enough

On a nearly equilateral triangle every multiple of three beats the inscribed circle, and to first order how long it keeps doing so depends only on the worst of the triangle's angle errors, which makes the window a hexagon in the plane of two errors. Fitted exactly, the window is a scalloped star. It reaches furthest — 21.8 degrees for the hexagon, against 15.6 and 19.1 on isosceles triangles — where one angle opens and another closes with the third left at sixty, because two sides still meet at sixty and the polygon can lie flush against both. Far outside it, wherever all three sides lie along the polygon's own directions, the polygon wins again.

construction · Optimal constructions

Named alongside it

The objects these essays reach for when they reach for this one.

Trade-offTree methodEfficiencySurface areaSurface in a volumeBox pleatingCircle packingGridToleranceThe decision problemDesign techniqueEnumeration

All concepts